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clc
clear
Th=0.22; //Thermal Efficiency
Hr=1260; //Heat Rejected in MJ/hr
CV=42; //Calorific Value of Coal
X=1-Th;
HI=Hr/X; //Heat Input in MJ/hr
O=((HI-Hr)*1000)/3600; //Output
Mf=HI/CV; //Mass of Fuel Used
printf('Power Output is %2.2f kW',O);
printf('\n');
printf('Mass of Fuel used per hour: %2.1f kg/hr',Mf);
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