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clear;
clc;
//Example 2.1
//Caption : Program to find Energy in a Waterfall
//Given values
H=100;//height=100m
M=1;//Mass of water=1Kg
g=9.8066;//Acceleration due to gravity(m/s^2)
//Solution
//Del(Energy of the system)=0
//hence,del(U)+del(KE)+del(PE)=0
//(a)
PE1=M*H*g;//(J)
disp('J',PE1,'(a)Potential energy of Water at the Top');
//(b)
del_U=0;
KE1=0;
PE2=0;
KE2=PE1;//(J)
disp('J',KE2,'(b)Kinetic energy of Water');
//(c)
del_U=KE2;
disp('J',del_U,'(c)Change in Internal energy when 1kg Water added');
//End
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