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// Exa 5.14.12
clc;
clear;
close;
// Given data
V_CC = 9;// in V
V_BE = 0.8;// in V
V_CE = 0.2;// in V
R_B = 50;// in kΩ
R_C=2;// in kΩ
R_E = 1;// in kΩ
bita=70;
// Applying KVL to input loop, V_CC= I_B*R_B +V_BE +I_E*R_E
// V_CC- V_BE= (R_B+R_E)*I_B + R_E*I_C (i)
// Applying KVL to output loop, V_CC= R_C*I_C +V_CE +I_C*R_E +I_B*R_E
//I_B = ((V_CC- V_CE)-(R_C+R_E)*I_C)/R_E (ii)
// From eq (i) and (ii)
I_C= ( (V_CC- V_BE)-(R_B+R_E)* (V_CC- V_CE)/R_E)/(1-(R_B+R_E)*(R_C+R_E));// in mA
I_B = ((V_CC- V_CE)-(R_C+R_E)*I_C)/R_E// in mA
I_Bmin= I_C/bita;// in mA
if I_B>I_Bmin then
disp("Since the value of I_B ("+string(I_B)+" mA) is greater than the value of I_Bmin ("+string(I_Bmin)+" mA)")
disp("So the transistor is in saturation ")
end
V_C= V_CC-I_C*R_C;// in V
disp(V_C,"The value of collector voltage in volts is : ")
bita= I_C/I_B;
disp(bita,"The minimum value of bita that will change the state of the trasistor is : ")
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