blob: 20fc88685052153a2fe82e18f353aff1539bef1c (
plain)
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
|
//Exa 4.16.3
clc;
clear;
close;
// Given data
Eta = 1;
V_T = 26;// in mV
V_T= V_T*10^-3;// in V
// I = I_o * (%e^(V/(Eta*V_T)) - 1) and I = -(0.9) * I_o;
V= log(1-0.9)*V_T;// in V
disp(V,"The voltage in volts is : ")
// Part (ii)
V1=0.05;// in V
V2= -0.05;// in V
ratio= (%e^(V1/(Eta*V_T))-1)/(%e^(V2/(Eta*V_T))-1)
disp(ratio,"The ratio of the current for a forward bias to reverse bias is : ")
// Part (iii)
Io= 10;// in µA
Io=Io*10^-3;// in mA
//For
V=0.1;// in V
I = Io * (%e^(V/(Eta*V_T)) - 1);// in mA
disp(I,"For V=0.1 V , the value of I in mA is : ")
//For
V=0.2;// in V
I = Io * (%e^(V/(Eta*V_T)) - 1);// in mA
disp(I,"For V=0.2 V , the value of I in mA is : ")
//For
V=0.3;// in V
I = Io * (%e^(V/(Eta*V_T)) - 1);// in mA
disp(I*10^-3,"For V=0.3 V , the value of I in A is : ")
disp("From three value of I, for small rise in forward voltage, the diode current increase rapidly")
|
