226/CH3/EX3.4/example4_sce.sce


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//chapter 3
//example 3.4
//page 84
printf("\n")
printf("given")
Eo=20;Rl=500;f=60;
Vr=(10*Eo)/100//10% of Eo
Il=Eo/Rl
T=1/f;
t1=T
C1=((Il*t1)/Vr)*10^6;
printf("reservior capacitance is %duF\n",C1)