226/CH3/EX3.24/example24_sce.sce


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//chapter 3
//example 3.24
//page 124
printf("\n")
printf("given")
f=500;Rs=600;E=8;
t=1/(2*f)
PW=t;
C1=PW/Rs
Vo=2*E
Vc=(1*Vo)/100;//1% of  the Vo
Ic=(Vc*C1)/t
R1=(2*E)/Ic;
printf("suitable value of R1 is %dohm\n",R1)