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//chapter 19
//example 19.9
//page 834
printf("\n")
printf("given")
hFE=2000;Vbe=1.4;Vp=10;Ip=200*10^-3;Icq2=20*10^-3;Re3=4.7;Re2=4.7;Vd=.7;
Ve1=3;Vc1=15.2;Vrc=Vc1;
Vb=Vbe+Icq*(Re2+Re3)+Vbe
Vcc=Vrc+Vc1+Vb
Ib2=Ip/hFE
Irc=1*10^-3;
Vrcac=4;
Rc=Vrcac/Irc
Ic1=Vrc/Rc
Rb=(Vb-(4*Vd))/Ic1
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