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// Chapter 6 example 18
//------------------------------------------------------------------------------
clc;
clear;
// Given data from fig
R_a = 1000; // resistance shown in fig a
W1 = 0.15*10^-3 // width of geometry fig 6.72a
L1 = 3*10^-3 // Length of geometry fig 6.72a
W2 = 75*10^-6 // width of geometry fig 6.72b
L2 = 1500*10^-6 // Length of geometry fig 6.72b
t1 = 10*10^-6 // thickness of geometry fig 6.72a
t2 = 20*10^-6 // thickness of geometry fig 6.72b
//R1 = ρs1*(L1/W1) // resistor geometry of fig 6.72a
//ρs1 = (R1*W1)/L1
ps1 = (R_a*W1)/L1 // sheet resistivity of geometry of fig 6.72a
p = ps1*t1; // resistivity
ps2 = p/t2; // sheet resistivity of geometry of fig 6.72b
R2 = ps2*(L2/W2); // resistance of geometry of fig 6.72b
// Output
mprintf('For Geometry in Fig 6.72b\n sheet resistivity = %3.0f Ω/□\n Resistance = %d Ω',ps2,R2)
//------------------------------------------------------------------------------
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