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//chapter 5 example 4
//=============================================================================
clc;
clear;
//Given Data
Va = 40*10^3;//Anode voltage of cross field amplifier
Ia = 15;//Anode current in Amp
Pin = 40*10^3;//input power in watts
G = 10;//gain in dB
n = 40/100;//overall efficiency converted from percentage to decimal
//Calculations
//Gain = (1+(Pgen/Pin))
Pgen = (G-1)*Pin//Generated power
ne = (Pgen/(Va*Ia))//electronic efficiency
nc = n/(ne)//circuit efficiency
Pout = Pin+(Pgen*nc)//output power
//Output
mprintf('Electronic Efficiency is %3.2f\n Output power is %g KW',ne,Pout/1000);
//=============================================================================
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