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// Chapter 3 example 15
//------------------------------------------------------------------------------
clc;
clear;
// Given data
a = 4*10^-2; // width of waveguide
b = 2*10^-2; // narrow dimension of waveguide
c = 3*10^8; // velocity of EM wave in m/s
m1 = 1; // for TE10
m2 = 2; // for TE20
n = 0; // for TE10
// Calculations
lamda_c = 2*a // cutoff wavelength for TE10 mode
f1 = c/lamda_c // frequency in Hz
// the frequency range for single mode operation is the range of frequencies corresponding to the dominant mode and the second highest cutoff wavelength
lamda_c_2 = 2/sqrt((m2/a)^2 + (n/b)^2)
f2 = c/lamda_c_2; // freq at second largest cutoff wavelength
// Output
mprintf('Therefore,single mode operating range = %3.2f Ghz to %3.1f Ghz\n',f1/10^9,f2/10^9 );
mprintf(' Note: instead of 3.75,3.5 is printed in textbook');
//------------------------------------------------------------------------------
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