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// chapter 2 example 12
//------------------------------------------------------------------------------
clc;
clear;
// given data
// E = 40π e^j(10^9t + βz)ax
// H = Hm e^j(10^9t + βz)ay
// w/β = 1/sqrt(e*uo) = 3*10^8
w = 10^9; // from given expression
b = w/3*10^8
Em = 40*%pi // from given expression
// E/H = 120; // for free space
Hm = Em/(120*%pi);
//V * E = -∂B/∂t
// =| ax ay az|
// V*E =| ∂/∂x ∂/∂y ∂/∂t|
// =|40π e^j(10^9t + βz) 0 0 |
// V*E = jβ40π e^j(10^9t + βz) ay ----- 1
// -∂B/∂t = uo*∂H/∂t = -j*10^9 *uo*Hm e^j(10^9t + βz)ay ----- 2
// Comparing 1 and 2 shoes that Hm must be negative Hence Hm = -1/3 A/m
mprintf('Hm = - %3.2f A/m',Hm);
//------------------------------------------------------------------------------
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