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//Chapter 6, Problem 6
clc
vbe=0.7 //base to emitter voltage
ic=1e-3 //collector current
vc=6 //collector voltage
vcc=12 //supply voltage
hf1=100 //dc current gain
hf2=250 //dc current gain
ibb=0.5e-3
//calculating the biasing resistors
ie=ic
hfe=sqrt(hf1*hf2)
ve=(10/100)*vcc
re=ve/ie
rc=((vcc-vc)/ic)
ib=ic/hfe
vbb=ve+vbe
r2=vbb/ibb
r1=((vcc-vbb)/(ibb+ib))
disp("Biasing resistor is given by\n")
printf("R1 = %.2f Kohm\nR2 = %.2f Kohm\nRc = %.2f Kohm\nRe = %.2f Kohm",r1/1000,r2/1000,rc/1000,re/1000)
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