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//Chapter 6, Problem 4
clc
vbe=0.7 //base to emitter voltage
ic=1e-3 //collector current
vc=6 //collector voltage
hf1=100 //dc current gain
hf2=250 //dc current gain
vcc=12 //supply voltage
vbb=1.5
ibb=0.5e-3
//calculating the biasing resistors
hfe=sqrt(hf1*hf2)
ib=ic/hfe
rb=((vbb-vbe)/ib)
r1=vbb/ibb
rf=((vc-vbb)/(ibb+ib))
rc=((vcc-vc)/(ic+ib+ibb))
disp("Biasing resistor is given by\n")
printf("R1 = %d Kohm\nRb = %.2f Kohm\nRc = %.2f Kohm\nRf = %.2f Kohm",r1/1000,rb/1000,rc/1000,rf/1000)
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