2159/CH7/EX7.14/714.sce


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// problem 7.14
i=1/2500
N=0.02
Q=14
n=1/(tand(60))
a=(3^0.5)
d=((Q*N*(2^0.6666))/((i^0.5)*a))^(3/8)
b=d*2/(3^0.5)
disp(d,b,"dimension of the channel")