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//example 3.15
//calculate
//duty of irrigation water
//discharge required
clc;
//Given
B=12; //transplantaion period
D=0.5; //total depth of water required by the crop
R=0.1; //rain falling on field
L=0.2; //loss of water
A=600; //irrigated area
I=0.6; //intensity of irrigation
delta=D-R;
Dui=8.64*B/delta;
//since water loss is 20 percent
Du=(1-L)*Dui;
mprintf("Duty of water required=%f hectares/cumec.",Du);
TA=I*A;
q=TA/Du;
q=round(q*100)/100;
mprintf("\nDischarge at head of water course=%f cumecs.",q);
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