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//Chapter-11 example 60
//=============================================================================
clc;
clear;
//Given data
PRF1 = 10*10^3; //pulse repetitive freq.1
PRF2 = 20*10^3; //pulse repetitive freq.2
Pav = 1000; // average tx. power
Pt = 10*10^3; // peak power
//Calculations
PRT1 = 1/PRF1; // pulse repetitive interval in sec
PRT2 = 1/PRF2; // pulse repetitive interval in sec
DC = Pav/Pt; // duty cycle
PW1 = DC*PRT1 // pulse width for freq1
PW2 = DC*PRT2 // pulse width for freq2
E1 = Pt*PW1; // energy of first pulse
E2 = Pt*PW2; // energy of second pulse
//output
mprintf('PW1 = %3.2f ms\n PW2 = %3.3f ms\n Pulse Energy for PRF = 10KHz is %3.1f Joules\n Pulse Energy for PRF = 20KHz is %3.2f Joules\n',PW1*1000,PW2*1000,E1,E2 );
//==============================================================================
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