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path: root/1985/CH1/EX1.4/chapter1_Example4.sce
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clc
clear

//INPUT DATA
L=1;//Length of pendulum in m
B=0.05;//Width of pendulum in m

//CALCULATIONS
k=sqrt((L^2+B^2)/12);//Radius of gyration in m
D=((L/2)-k)*100;//distance of point of minimum time period from one end in cm

//OUTPUT
mprintf('The minimum time period is obtained at %3.2f cm',D)