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//Chapter-3,Example 3_3,Page 3-19
clc()
//Given Data:
n1=1.48 //R.I. of Core
n2=1.39 //R.I. of Cladding
//Calculations:
NA=sqrt(n1^2-n2^2) //Formula to find NA
phi=asin(NA)*180/%pi //Acceptance angle
printf('Numerical Aperture of Fibre is = %.3f \n \n',NA)
printf(' Acceptance angle of Fibre is =%.1f degrees',phi)
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