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//Chapter-3,Example 3_12,Page 3-22
clc()
//Given Data:
u1=1.5 //R.I. of Core
d=10*10^-6 //diameter of core
a=d/2 //core radius
lam=1.3*10^-6 //wavelength
V=2.405 //cut off parameter for single mode
//Calculations:
//We know, V=2*%pi*a*NA/lam
NA=V*lam/(2*%pi*a) //Numerical Aperture
theta=asin(NA)*180/%pi //Acceptance angle
printf('Acceptance angle of Fibre is =%.2f degrees \n \n',theta)
//Also, NA=u1*sqrt(2*del)
del=(NA/u1)^2/2 //Fractional index
printf(' Maximum Fractional Refractive index of Fibre is =%.4f \n \n',del)
//del=(u1-u2)/u1
u2=u1*(1-del) //R.I.of cladding
printf(' Refractive index of cladding of Fibre is =%.3f \n',u2)
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