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// Theory and Problems of Thermodynamics
// Chapter 4
// Energy Analysis of Process
// Example 8
clear ;clc;
//Given data
T1 = 200 // entering Temperature in C
P1 = 0.5 // Entering steam Pressure in MPa
P2 = 0.1 // leaving steam Pressure in MPa
vel_1 = 1 // inlet velocity in m/s
m_f = 1 // mass flow rate
Q = -10 // Energy lost as heat in kJ/s
// from superheated steam tables at P = 0.5 MPa and T = 200
h1 = 2855.4 // units kJ/kg
// from saturated steam tables at P = 0.1 MPa
h2 = 2675.5 // units kJ/kg
// Calculation for Exit velocity of gas
V2 = sqrt(2*(Q+h1-h2)* 1e3 +1)
// Output Results
mprintf('Exit velocity of steam = %6.2f m/s',V2)
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