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// Theory and Problems of Thermodynamics
// Chapter 2
// First Law of Thermodynamics
// Example 4
clear ;clc;
//Given data
T = 303 // initial temperature in K
P = 100 // initial pressure in kPa
V_w = 0.001004 // specific volume for water in m3/kg
V_v = 1.694910 // specific volume for vapor in m3/kg
H_w = 125.6 // enthalpy of water in kJ/kg
H_v = 2675.47 // enthalphy of vapor in kJ/kg
// determine heat and work interactions
W = P * (V_v - V_w); // work interaction
del_H = H_v - H_w // enthalpy difference
Q = del_H //heat interaction
// Results
mprintf('Work interaction = %7.2f kJ', W)
mprintf('\n Heat interaction = %5.2f kJ', Q)
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