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clear all; clc;
disp("Scilab Code Ex 5.21 : ")
//Given:
l = 1.5; //m
G = 42*10^3; //GPa
co = 50; //mm
ci = 25;//mm
shear_y = 84; //N/mm^2
strain_y = 0.002; //rad
//Plastic Torque:
T_p = ((2*%pi)*(co^3 - ci^3)*shear_y)/3;
phi_p = (strain_y*l*10^3)/ci;
J = (%pi/2)*(co^4 - ci^4);
shear_r = (T_p*co)/J;
shear_i = (shear_r*ci)/(co);// shear = Tc/J
G = shear_y/strain_y;
phi_dash = (T_p*l*10^3)/(J*G); //phi = TpL/JG;
phi = phi_p - phi_dash;
T_p = T_p/10^6;
//Display:
printf('\n\nThe plastic torque Tp = %1.2f x 10^6 Nmm',T_p);
printf('\nThe permanent twist of the tube if Tp is removed = %1.5f rad',phi);
//----------------------------------------------------------------END------------------------------------------------------------------------
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