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clear all; clc;
disp("Scilab Code Ex 1.10 : ")
//Given:
af = 800; //N Axial force along centroidal axis
t = 0.040; //m thickness of square cross section
ang_b = 30 *(%pi/180) ;
ang_b_comp = 60 *(%pi/180);
a = t^2; //m^2 Area of cross section
a_new = ((t*1000)^2)/(sin(ang_b_comp)); // mm^2 Area of section at b-b
//Part(a)
//Internal Loading: The bar is sectioned, Fig 1-24b, and the internal resultant loading consists of only axial force.
// Average Stress:
avg_stress = af/(a* 1000);
//Shear Force at the section is zero.
//The average normal stress distribution over the cross section is shown in Fig 1-24c.
//Part(b)
//solve the two equations for two unknowns:
N = af * cos(ang_b);
V = af * sin(ang_b);
avg_normal_stress = (N*1000)/ a_new; // kPa
avg_shear_stress = (V*1000)/a_new; //kPa
//Display
printf('\n\nThe average stress for section a-a = %.2f kPa',avg_stress);
printf('\nThe Normal Force for section b-b = %.2f N',N);
printf('\nThe Shear Force for section b-b = %.2f N',V);
printf('\nThe Average Normal Stress for section b-b = %.2f kPa',avg_normal_stress);
printf('\nThe Average Shear Stress for section b-b = %.2f kPa',ceil(avg_shear_stress));
//--------------------------------------------------------------------------END--------------------------------------------------------------------------
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