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//Chapter-3,Example3_3_2,pg 3-6
NA=0.2 //Numerical aperture
n2=1.59 //refractive index of cladding
n1=sqrt(n2^2-NA^2) //Numerical aperture is 'NA^2 = n1^2 - n2^2'
printf("\nThe refractive index of core is n1 = %.1f\n",n1)
n0=1.33 //refractive index of medium
angle_0=asind(NA/n0) //For medium numerical aperture is 'NA=n0*sin(angle_0)'
printf("\nThe acceptance angle is angle_0 = %.2f Degree\n",angle_0)
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