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// Scilab code Ex7.11: Pg:307 (2008)
clc;clear;
P = 3.2e+07/1.6e-013; // Power developed by the reactor, MeV
E = 200; // Energy released by the reactor per fission, MeV
n = P/E; // Number of fissions occuring in the reactor per second, per sec
N = n*1000*3600; // Number of atoms or nuclei of Uranium 235 consumed in 1000 hours
// Since the number of atoms in 235 g of Uranium is 6e+023
M = N/6e+023*235/1000; // Mass of Uranium 235 consumed in 1000 hours, kg
printf("\nThe number of atoms of Uranium 235 undergoing fission per second = %4.1e ", N);
printf("\nThe mass of Uranium 235 consumed in 1000 hours = %4.2f kg ", M);
// Result
// The number of atoms of Uranium 235 undergoing fission per second = 3.6e+024
// The mass of Uranium 235 consumed in 1000 hours = 1.41 kg
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