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// Scilab code Ex4.22 : Pg:159 (2008)
clc;clear;
lambda = 5890e-008; // Wavelength of light used, cm
n = 12; // Number of bright fringe to which the central fringe shifts
mu = 1.60; // The refractive index of transparent material
t = n*lambda/(mu-1); // Thickness of transparent material, cm
printf("\nThe thickness of the transparent material = %5.3e cm", t);
// Result
// The thickness of the transparent material = 1.178e-003 cm
// The answer is given wrong in the textbook
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