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// Scilab Code Ex2.56:: Page-2.46(2009)
clc; clear;
R = 1; // For simplicity assume radius of curvature of the lens to be unity, cm
D_n = 0.251; // Diameter of 3rd dark ring, cm
D_nplusp = 0.548; // Diameter of 9th dark ring, cm
n = 3; // Order of 3rd Newton ring
p = 9 - n; // Order of 6th Newton ring from 3rd ring
// As D_nplusp^2 - D_n^2 = 4*p*R*lambda, solving for lambda
lambda = (D_nplusp^2 - D_n^2)/(4*p*R); // Wavelength of light used
D_15 = sqrt(D_n^2+4*(15-n)*lambda*R); // Diameter of 15th dark ring, cm
printf("\nThe diameter of 15th dark ring = %5.3f cm", D_15);
// Result
// The diameter of 15th dark ring = 0.733 cm
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