blob: d38835a9fd8de1f971bf9d7973fde8445f8b3959 (
plain)
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
|
//CHAPTER 5 ILLUSRTATION 3 PAGE NO 161
//TITLE:Inertia Force Analysis in Machines
clc
clear
pi=3.141
D=.3// Diameter of steam engine in m
L=.5// length of stroke in m
r=L/2
mR=100// equivalent of mass of reciprocating parts in kg
N=200// speed of engine in rpm
teeta=45// angle of inclination of crank in degrees
p1=1*10^6// gas pressure in N/m^2
p2=35*10^3// back pressure in N/m^2
n=4// ratio of crank radius to the length of stroke
//=================================
w=2*pi*N/60// angular speed in rad/s
Fl=pi/4*D^2*(p1-p2)// Net load on piston in N
Fi=mR*w^2*r*(cosd(teeta)+cosd(2*teeta)/(2*n))// inertia force due to reciprocating parts
Fp=Fl-Fi// Piston effort
T=Fp*r*(sind(teeta)+(sind(2*teeta))/(2*(n^2-(sind(teeta))^2)^.5))
printf('Piston effort = %.3f N\n Turning moment on the crank shaft = %.3f N-m',Fp,T)
|
