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//CHAPTER 12 ILLUSRTATION 1 PAGE NO 310
//TITLE:Balancing of reciprocating of masses
clc
clear
pi=3.141
N=250// speed of the reciprocating engine in rpm
s=18// length of stroke in mm
mR=120// mass of reciprocating parts in kg
m=70// mass of revolving parts in kg
r=.09// radius of revolution of revolving parts in m
b=.15// distance at which balancing mass located in m
c=2/3// portion of reciprocating mass balanced
teeta=30// crank angle from inner dead centre in degrees
//===============================
B=r*(m+c*mR)/b// balance mass required in kg
w=2*pi*N/60// angular speed in rad/s
F=mR*w^2*r*(((1-c)^2*(cosd(teeta))^2)+(c^2*(sind(teeta))^2))^.5// residual unbalanced forces in N
printf('Magnitude of balance mass required= %.0f kg\n Residual unbalanced forces= %.3f N',B,F)
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