path: root/1826/CH2/EX2.31/ex2_31.sce

// Example 2.31, page no-49
clear
clc
a=0.4049*10^-10//m
t=0.005//m
A=25*10^-2//m
n=t*A/a^3
printf("The number of atoms in the Al foil is %.2f * 10^28",n*10^-28)