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//Example7.1 // Design active low filter with cut-off frequency 10 KHz
clc;
clear;
close;
fc = 10 ; // KHz
C = 0.01 ; //uF // we assume
// the cut-off frequency of active low pass filter is defined as
// fc = (1/2*%pi*R3*C);
// R3 can be calculated as
R3 = (1/(2*%pi*fc*C));
disp('The resistor value is = '+string(R3)+' k ohm ');
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