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// Scilab Code Ex 1.14 :Page-26 (2006)
clc; clear;
R = 1; // For simplicity we assume radius of atom to be unity, m
// For bcc Structure,
a = 4*R/sqrt(3); // Lattice parameter of bcc crystal, m
// We have (R+r)^2 = (a/2)^2+(a/4)^2, solving for r
r = a/2-R // Relation between radius of the void and radius of the atom, m
printf("\nThe radius of void for carbon atoms in iron = %5.3fR", r);
// Result
//The radius of void for carbon atoms in iron = 0.155R
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