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// Scilab Code Ex 1.12 :Page-25 (2006)
clc; clear;
R = 1; // For simplicity we assume radius of atom to be unity, m
// For fcc Structure,
a = 4*R/sqrt(2); // Lattice parameter of fcc crystal, m
// We have R+r = a/2, solving for r
r = a/2-R // Relation between radius of the void and radius of the atom, m
printf("\nThe maxiumum radius of the sphere that can fit into void between two fcc unit cells = %5.3fR", r);
// Result
// The maxiumum radius of the sphere that can fit into void between two fcc unit cells = 0.414R
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