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//example 2
//work done for adding the fluid
clear
clc
P=600 //pressure in kPa
m=1 //in kg
v=0.001 //specific volume in m^3/kg
W=P*m*v //necessary work in kJ for adding the fluid
printf(" \n hence,the work involved in this process is W=%.3f kJ. \n",W)
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