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//example 4
//calculating work done
clear
clc
v1=0.35411 //specific volume at state 1 in m^3/kg
v2=v1/2
m=0.1 //mass of water in kg
P1=1000 //pressure inside cylinder in kPa
W=m*P1*(v2-v1) //in kJ
disp('hence,the work in the overall process is -17.7 kJ')
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