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//Example 5.2
clc
disp("From equation 9 we have")
disp(" BW = 1 / 2*pi*R*C")
rc=1/(2*%pi*10*10^3)
format(12)
disp(rc,"Therefore, R*C = 1 / 2*pi*BW =")
disp("From equation 3 we have")
disp(" R = r_i || R_p || r_b''e")
disp("where r_i = 4 k-ohm")
rbe=100/0.04
disp(rbe,"r_b''e(in ohm) = h_fe / g_m =")
disp("R_p = Q_c * omega_0 * L = Q_c / omega_0*C")
disp("Therefore, R = 4*10^3 || 2500 || Q_c/omega_0*C")
disp("C = 1 / 2*pi*10*10^3*R")
disp("Therefore, C = 1 / 2*pi*10*10^3*[4*10^3 || 2500 || Q_c/2*pi*500*10^3*C]")
disp("The typical range for Q_c is 10 to 150. However, we have to assume Q such that value of C_p should be positive. Let us assume Q = 100")
disp("Therefore, C = 1 / 2*pi*10*10^3*[1538.5 || 1/2*pi*5000*C]")
disp(" = 1 / 2*pi*10*10^3*[1 / 1/1538.5+2*pi*5000*C]")
disp("Solving for C we get")
disp(" C = 0.02 uF")
disp("We have")
disp(" C = C'' + C_b''e + (1+g_m*R_L)*C_b''e")
disp("Therefore, C'' = C - [C_b''e + (1+g_m*R_L)*C_b''e]")
c=((0.02*10^-6)-[(1000*10^-12)+((1+(0.04*510))*100*10^-12)])*10^6
format(8)
disp(c,"Therefore, C''(in uF) =")
disp("We have,")
disp("omega_0^2 = 1 / L*C")
l=(1/(((2*%pi*500*10^3)^2)*(0.02*10^-6)))*10^6
format(2)
disp(l,"Therefore, L(in uH) = 1 / omega_0^2*C =")
disp("From equation 2 we have,")
rp=2*%pi*500*5*100*10^-3
format(5)
disp(rp,"R_p(in ohm) = omega*L*Q_c =")
r=(4000*1570*2500)/((1570*2500)+(4000*2500)+(4000*1570))
format(4)
disp(r,"Therefore, R(in ohm) = r_i || R_p || r_b''e =")
disp("We have mid frequency gain as")
av=-0.04*777
disp(av,"A_v(max) = -g_m*R =")
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