blob: 41851bfb40d68d5e6c12c405120ad86a52e7ced7 (
plain)
1
2
3
4
5
6
7
8
9
10
11
|
//Example 2.17
clc
disp("R = 6 k-ohm, C = 1500 pF, R_C = 18 k-ohm")
k=18/6
disp(k,"Now K = R_C / R =")
disp("Therefore, f = 1 / 2*pi*R*C*sqrt(6+4K)")
f=(1/(2*%pi*(6*10^3)*(1500*10^-12)*sqrt(6+12)))*10^-3 // in kHZ
format(6)
disp(f," f(in kHz) =")
hfe=(4*3)+23+(29/3)
disp(hfe," (h_fe)min = 4K + 23 + 29/K =")
|
