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//Example 2.13
clc
disp("Given, C1 = 100 pF, C2 = 50 pF, f = 10 MHz, L = ?")
ceq=(5000*10^-24)/(150*10^-12)
format(10)
disp(ceq,"C_eq(in F) = C1*C2 / C1+C2 = ")
disp("f = 1 / 2*pi*sqrt(L*C_eq)")
l=(1/(4*(%pi^2)*(33.33*10^-12)*((10*10^6)^2)))*10^6 // in F
format(4)
disp(l,"Therefore, L(in uH) =")
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