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// Example 9.16.1 page 9.53
clc;
clear;
Pin=2;
Pout=27;
gain_db= Pout-Pin;
gain= 10^(Pout/10)/10^(Pin/10);
min_pow = 10^(Pout/10) - 10^(Pin/10);
printf("\nGain in dB is %d dB.\nGain is %.2f.\nMinimum pump power is %.1f mW.",gain_db,gain,min_pow);
//answer in the book for gain is 317, deviation of 0.77 and for minimum pump power it is 499.4, deviation of 0.2
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