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//Example 4.20
close;
clc;
V=3; //in volts
Rm=100; //In ohms
Rh=1000; //In ohms
Ifsd=1*10^-3; //in amperes
//Calculation of R1
R1=Rh-Ifsd*Rm*Rh/V;
//Calculation of R2
R2=Ifsd*Rm*Rh/(V-Ifsd*Rh);
//R2 compensation
drop=3; //by percent
V=V-drop*V/100;
R2new=Ifsd*Rm*Rh/(V-Ifsd*Rh);
printf('\nValue of R1 = %.2f ohm\n',R1)
printf('\nValue of R2 = %.2f ohm\n',R2)
printf('\nValue of R2 after compensation = %.2f ohm\n',R2new)
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