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//Example 11.5
clc;
E=6; //Applied potential across bridge
//Given values of bridge elements
R1=5000;
R2=5000;
R3=5000;
//We Know Balanced bridge equations as
// R1*R3=R2*R4
Rv=R2*R3/R1;
disp(Rv,'Value of unknown Resistence Rv is at 80 deg C')
//Now given from the graph is the value of Rv at 60 deg C
Rv=4500;
//The error signal can be calculated using following formula
es=E*(R3/(R1+R3)-Rv/(R2+Rv));
disp(es,'The value of error signal at 60 deg C is')
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