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//Example 11.3
clc;
//Given values of bridge elements
R=700; //R1=R2=R3=R
R4=735; //R4=R+del_R
Rg=125; //Galvanometer resistence
E=10; //Applied potential across bridge
del_R=R4-R;
//Thevenin's equivalent voltage
Eth=0.25*E*del_R/R;
//Thevenin's equivalent resistence
Rth=R;
//Current through the Galvanometer
Ig=Eth/(Rth+Rg);
disp(Ig,'Current through the Galvanometer')
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