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// Examle 3.26
// Reffer Diagram (3.44a)
// First of all convert all resistor in to conductor
// From the obtained diagram (3.44c) Apply KCL to node 1 & 2
// Node-1 0.7S1-0.2S2-= 3..................(i
// Node-2 -0.2S1-1.2S2= 2..................(ii
// By using matrix form will get A*X = B formate
delta=[0.7 -0.2 ; -0.2 1.2 ]; // value of A
d=det(delta); // Determinant of A
delta1=[3 -0.2 ; 2 1.2 ]; // value of A1 (when 1st colomn is replace by B)
d1=det(delta1); // Determinant of A1
delta2=[0.7 3 ; -0.2 2 ]; // value of A2 (when 2nd colomn is replace by B)
d2=det(delta2); // Determinant of A2
V1=d1/d; // Voltage at node-1
V2=d2/d; // Voltage at node-2
I=(V1-V2)/5; // Current through 5 ohm resistor (I)
disp(' Current through 5 ohm resistor = '+string(I)+' Amp');
// p 84 3.26
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