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// Example 2.9
// From the diagram 2.18
// Minimum value of Req is obtained if R=0
// Maximum value of Req is obtained if R= Open ckt
R1=30; // Given the value of R1 & R1+R2= 75
R2=75-R1; // The value of R2
disp(' The value of R1 is = '+string(R1)+' Ohms ');
disp(' The value of R2 is = '+string(R2)+' Ohms ');
// From the diagram 2.19
Req= (30+75)/2; // Required value of Req is Req= (30+75)/2
Rp=Req-R1; // Hance the parallel combination of R2 & R
disp(' The value of Rp is = '+string(Rp)+' Ohms ');
disp('The value of Rp is exactly half of R2= 45, hance the value of R should be '+string(R2)+' Ohms ');
// p 26 2.9
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