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// Examle 16.8
po=30000; // o/p power
v=200; // Voltage
Il=po/v; // Load Current (Il)
disp(' Load Current (Il) = '+string(Il)+' Amp');
Rsh=50; // Shunt field resistance R1
Ish=v/Rsh; // Shunt field Current
Ia=Il+Ish; // Armature Current (Ia)
Ra=0.05; // Shunt field resistance R2
Eg=v+(Ia*Ra); // Generated emf (Eg)
disp('Generated emf (Eg) = '+string(Eg)+' Volt');
Cu=Ish^2*Rsh+Ia^2*Ra; // The copper Losses (Cu)
disp('The copper Losses (Cu) = '+string(Cu)+' W');
e=po*100/(1000+po+Cu); // The Efficiency (e)
disp('The Efficiency (e) = '+string (e)+' %');
// p 641 16.8
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