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// Example 2.2.1 page 2.4
clc;
clear;
alpha= 3; // average loss Power decreases by 50% so P(0)/P(z)= 0.5
lamda= 900*10^-9; //wavelength
z= 10*log10(0.5)/alpha; //z is the length
z= z*-1;
printf("The length over which power decreases by 50%% is =%.2f Kms",z);
z1= 10*log10(0.25)/alpha; //Power decreases by 75% so P(0)/P(z)= 0.25
z1=z1*-1; //as distance cannot be negative...
printf("\n\nThe length over which power decreases by 75%% is =%.2f Kms",z1);
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