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//Example 1.14.12
//To find noramlised frequency and number of modes
clc;
clear;
lamda= 850*10^-9; //wavelength of operation.
a= 25*10^-6; //Radius of core
n1= 1.48; //RI of Core...
n2= 1.46; //RI of cladding..
NA= sqrt(n1^2-n2^2); //Numerical Aperture
V= 2*%pi*a*NA/lamda; //Normalised frequency..
printf('The normalised frequency is %.2f',V);
lamda1= 1320*10^-9; // wavelength changed...
V1= 2*%pi*a*NA/lamda1; //Normalised frequency at new wavelength..
M= V1^2/2; //Number of modes at new wavelength..
printf("\n\nThe number of modes in the fibre at 1320um are %d",M);
lamda2= 1550*10^-9; //wavelength 2...
V2= 2*%pi*a*NA/lamda2; //New normalised frequency..
M1= V2^2/2; // number of modes..
printf("\n\nThe number of modes in the fibre at 1550um are %d",M1);
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