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// Scilab Code Ex3.1 : Page-3.4 (2004)
// In a SC structure number of planes are having three arrangement (100),(110) and (111)
clc;clear;
a = 1; // For simplicity lattice constant is taken to be unity
A_100 = a^2; // Area of the plane (100), mm^2
N_100 = 1/A_100; // Number of atoms along (100) plane, atoms per square mm
A_110 = sqrt(2)*a^2; // Area of the plane (110), mm^2
N_110 = 1/A_110; // // Number of atoms along (110) plane, atoms per square mm
A_111 = 1/2*a*sqrt(2)*sqrt(2)*a^2*cosd(30); // Area of the plane (110), mm^2
A_111t = 0.5; // Total no of atoms in (111) plane
N_111 = A_111t/A_111; // // Number of atoms along (110) plane, atoms per square mm
printf("\nNumber of atoms along (100) plane= %d /a^2 atoms per square mm", N_100);
printf("\nNumber of atoms along (110) plane= %f atoms per square mm", N_110);
printf("\nNumber of atoms along (111) plane= %5.3f /a^2 atoms per square mm", N_111);
// Result
// Number of atoms along (100) plane= 1 /a^2 atoms per square mm
// Number of atoms along (110) plane= 0.707107 atoms per square mm
// Number of atoms along (111) plane= 0.577 /a^2 atoms per square mm
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