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clc
clear
//INPUT
t=295;//temperature of water in K
dp=10^6;//cahnge in pressure in dyne/sq.cm
j=4.2*10^7;//joules constant in ergs/cal
//CALCULATIONS
dc=-t*10^-5*dp/j;//change in specific heat
//OUTPUT
mprintf('the change in specific heat is %3.7f cal/degree',dc)
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