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//chapter 10 Ex 3
clc;
clear;
close;
n1=2.125/25; n2=6.3/9; n3=.04/.25;
mprintf("(i)%.1f percent of 25=2.125\n (ii)9 percent of %.0f =63\n (iii)0.25 percent of %.0f = .04",n1*100,n2*100,n3*100);